6(3x+1)=8(8x+6)+8

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Solution for 6(3x+1)=8(8x+6)+8 equation: 



6(3x+1)=8(8x+6)+8

We move all terms to the left:

6(3x+1)-(8(8x+6)+8)=0

We multiply parentheses

18x-(8(8x+6)+8)+6=0



We calculate terms in parentheses: -(8(8x+6)+8), so:

8(8x+6)+8

We multiply parentheses

64x+48+8

We add all the numbers together, and all the variables

64x+56

Back to the equation:

-(64x+56)



We get rid of parentheses

18x-64x-56+6=0

We add all the numbers together, and all the variables

-46x-50=0

We move all terms containing x to the left, all other terms to the right

-46x=50

x=50/-46

x=-1+2/23

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