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6(3x+2)+5(12x-6)-12x=6(x-3)+15(6x+5)
We move all terms to the left:
6(3x+2)+5(12x-6)-12x-(6(x-3)+15(6x+5))=0
We add all the numbers together, and all the variables
-12x+6(3x+2)+5(12x-6)-(6(x-3)+15(6x+5))=0
We multiply parentheses
-12x+18x+60x-(6(x-3)+15(6x+5))+12-30=0
We calculate terms in parentheses: -(6(x-3)+15(6x+5)), so:We add all the numbers together, and all the variables
6(x-3)+15(6x+5)
We multiply parentheses
6x+90x-18+75
We add all the numbers together, and all the variables
96x+57
Back to the equation:
-(96x+57)
66x-(96x+57)-18=0
We get rid of parentheses
66x-96x-57-18=0
We add all the numbers together, and all the variables
-30x-75=0
We move all terms containing x to the left, all other terms to the right
-30x=75
x=75/-30
x=-2+1/2
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