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6(3x+2)+5(7x-6)-12x=5(6x-1)+6(x-3)
We move all terms to the left:
6(3x+2)+5(7x-6)-12x-(5(6x-1)+6(x-3))=0
We add all the numbers together, and all the variables
-12x+6(3x+2)+5(7x-6)-(5(6x-1)+6(x-3))=0
We multiply parentheses
-12x+18x+35x-(5(6x-1)+6(x-3))+12-30=0
We calculate terms in parentheses: -(5(6x-1)+6(x-3)), so:We add all the numbers together, and all the variables
5(6x-1)+6(x-3)
We multiply parentheses
30x+6x-5-18
We add all the numbers together, and all the variables
36x-23
Back to the equation:
-(36x-23)
41x-(36x-23)-18=0
We get rid of parentheses
41x-36x+23-18=0
We add all the numbers together, and all the variables
5x+5=0
We move all terms containing x to the left, all other terms to the right
5x=-5
x=-5/5
x=-1
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