6(3x+2)+8(5x+2)=x-1

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Solution for 6(3x+2)+8(5x+2)=x-1 equation: 



6(3x+2)+8(5x+2)=x-1

We move all terms to the left:

6(3x+2)+8(5x+2)-(x-1)=0

We multiply parentheses

18x+40x-(x-1)+12+16=0

We get rid of parentheses

18x+40x-x+1+12+16=0

We add all the numbers together, and all the variables

57x+29=0

We move all terms containing x to the left, all other terms to the right

57x=-29

x=-29/57

x=-29/57

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