6(3x+2)-5(6x-1)=2(x-8)-5(7x-6)+8x

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Solution for 6(3x+2)-5(6x-1)=2(x-8)-5(7x-6)+8x equation:



6(3x+2)-5(6x-1)=2(x-8)-5(7x-6)+8x
We move all terms to the left:
6(3x+2)-5(6x-1)-(2(x-8)-5(7x-6)+8x)=0
We multiply parentheses
18x-30x-(2(x-8)-5(7x-6)+8x)+12+5=0
We calculate terms in parentheses: -(2(x-8)-5(7x-6)+8x), so:
2(x-8)-5(7x-6)+8x
We add all the numbers together, and all the variables
8x+2(x-8)-5(7x-6)
We multiply parentheses
8x+2x-35x-16+30
We add all the numbers together, and all the variables
-25x+14
Back to the equation:
-(-25x+14)
We add all the numbers together, and all the variables
-12x-(-25x+14)+17=0
We get rid of parentheses
-12x+25x-14+17=0
We add all the numbers together, and all the variables
13x+3=0
We move all terms containing x to the left, all other terms to the right
13x=-3
x=-3/13
x=-3/13

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