6(3x+2)=-3(x+11)

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Solution for 6(3x+2)=-3(x+11) equation: 



6(3x+2)=-3(x+11)

We move all terms to the left:

6(3x+2)-(-3(x+11))=0

We multiply parentheses

18x-(-3(x+11))+12=0



We calculate terms in parentheses: -(-3(x+11)), so:

-3(x+11)

We multiply parentheses

-3x-33

Back to the equation:

-(-3x-33)



We get rid of parentheses

18x+3x+33+12=0

We add all the numbers together, and all the variables

21x+45=0

We move all terms containing x to the left, all other terms to the right

21x=-45

x=-45/21

x=-2+1/7

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