6(3x+2)=2x+20

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Solution for 6(3x+2)=2x+20 equation: 



6(3x+2)=2x+20

We move all terms to the left:

6(3x+2)-(2x+20)=0

We multiply parentheses

18x-(2x+20)+12=0

We get rid of parentheses

18x-2x-20+12=0

We add all the numbers together, and all the variables

16x-8=0

We move all terms containing x to the left, all other terms to the right

16x=8

x=8/16

x=1/2

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