6(3x+2)=3x-4-x

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Solution for 6(3x+2)=3x-4-x equation: 



6(3x+2)=3x-4-x

We move all terms to the left:

6(3x+2)-(3x-4-x)=0

We add all the numbers together, and all the variables

6(3x+2)-(2x-4)=0

We multiply parentheses

18x-(2x-4)+12=0

We get rid of parentheses

18x-2x+4+12=0

We add all the numbers together, and all the variables

16x+16=0

We move all terms containing x to the left, all other terms to the right

16x=-16

x=-16/16

x=-1

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