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6(3x+3)=3(2x+4)
We move all terms to the left:
6(3x+3)-(3(2x+4))=0
We multiply parentheses
18x-(3(2x+4))+18=0
We calculate terms in parentheses: -(3(2x+4)), so:We get rid of parentheses
3(2x+4)
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
18x-6x-12+18=0
We add all the numbers together, and all the variables
12x+6=0
We move all terms containing x to the left, all other terms to the right
12x=-6
x=-6/12
x=-1/2
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