6(3x+4x-8)=120

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Solution for 6(3x+4x-8)=120 equation: 



6(3x+4x-8)=120

We move all terms to the left:

6(3x+4x-8)-(120)=0

We add all the numbers together, and all the variables

6(7x-8)-120=0

We multiply parentheses

42x-48-120=0

We add all the numbers together, and all the variables

42x-168=0

We move all terms containing x to the left, all other terms to the right

42x=168

x=168/42

x=4

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