6(3x-11)+80=11x+45

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Solution for 6(3x-11)+80=11x+45 equation: 



6(3x-11)+80=11x+45

We move all terms to the left:

6(3x-11)+80-(11x+45)=0

We multiply parentheses

18x-(11x+45)-66+80=0

We get rid of parentheses

18x-11x-45-66+80=0

We add all the numbers together, and all the variables

7x-31=0

We move all terms containing x to the left, all other terms to the right

7x=31

x=31/7

x=4+3/7

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