6(3x-2)=19x-7(x-6)

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Solution for 6(3x-2)=19x-7(x-6) equation:



6(3x-2)=19x-7(x-6)
We move all terms to the left:
6(3x-2)-(19x-7(x-6))=0
We multiply parentheses
18x-(19x-7(x-6))-12=0
We calculate terms in parentheses: -(19x-7(x-6)), so:
19x-7(x-6)
We multiply parentheses
19x-7x+42
We add all the numbers together, and all the variables
12x+42
Back to the equation:
-(12x+42)
We get rid of parentheses
18x-12x-42-12=0
We add all the numbers together, and all the variables
6x-54=0
We move all terms containing x to the left, all other terms to the right
6x=54
x=54/6
x=9

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