6(3x-2)=2(2x+1)

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Solution for 6(3x-2)=2(2x+1) equation: 



6(3x-2)=2(2x+1)

We move all terms to the left:

6(3x-2)-(2(2x+1))=0

We multiply parentheses

18x-(2(2x+1))-12=0



We calculate terms in parentheses: -(2(2x+1)), so:

2(2x+1)

We multiply parentheses

4x+2

Back to the equation:

-(4x+2)



We get rid of parentheses

18x-4x-2-12=0

We add all the numbers together, and all the variables

14x-14=0

We move all terms containing x to the left, all other terms to the right

14x=14

x=14/14

x=1

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