6(3x-2)=2/5(10x-5)+18

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Solution for 6(3x-2)=2/5(10x-5)+18 equation: 



6(3x-2)=2/5(10x-5)+18

We move all terms to the left:

6(3x-2)-(2/5(10x-5)+18)=0



Domain of the equation: 5(10x-5)+18)!=0

x∈R



We multiply parentheses

18x-(2/5(10x-5)+18)-12=0

We multiply all the terms by the denominator


18x*5(10x-5)-12*5(10x-5)+18)-(2+18)=0

We add all the numbers together, and all the variables

18x*5(10x-5)-12*5(10x-5)+18)-20=0

We add all the numbers together, and all the variables

18x*5(10x-5)-12*5(10x-5)=0

Wy multiply elements

90x^2(1-60x(1=0

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