6(3x-2)=3(x+9)

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Solution for 6(3x-2)=3(x+9) equation:



6(3x-2)=3(x+9)
We move all terms to the left:
6(3x-2)-(3(x+9))=0
We multiply parentheses
18x-(3(x+9))-12=0
We calculate terms in parentheses: -(3(x+9)), so:
3(x+9)
We multiply parentheses
3x+27
Back to the equation:
-(3x+27)
We get rid of parentheses
18x-3x-27-12=0
We add all the numbers together, and all the variables
15x-39=0
We move all terms containing x to the left, all other terms to the right
15x=39
x=39/15
x=2+3/5

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