6(3x-2)=7(2x+4)

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Solution for 6(3x-2)=7(2x+4) equation: 



6(3x-2)=7(2x+4)

We move all terms to the left:

6(3x-2)-(7(2x+4))=0

We multiply parentheses

18x-(7(2x+4))-12=0



We calculate terms in parentheses: -(7(2x+4)), so:

7(2x+4)

We multiply parentheses

14x+28

Back to the equation:

-(14x+28)



We get rid of parentheses

18x-14x-28-12=0

We add all the numbers together, and all the variables

4x-40=0

We move all terms containing x to the left, all other terms to the right

4x=40

x=40/4

x=10

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