6(3x-2)=8(2x-1)

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Solution for 6(3x-2)=8(2x-1) equation: 



6(3x-2)=8(2x-1)

We move all terms to the left:

6(3x-2)-(8(2x-1))=0

We multiply parentheses

18x-(8(2x-1))-12=0



We calculate terms in parentheses: -(8(2x-1)), so:

8(2x-1)

We multiply parentheses

16x-8

Back to the equation:

-(16x-8)



We get rid of parentheses

18x-16x+8-12=0

We add all the numbers together, and all the variables

2x-4=0

We move all terms containing x to the left, all other terms to the right

2x=4

x=4/2

x=2

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