6(3x-2)=9(2x-1)+-3

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Solution for 6(3x-2)=9(2x-1)+-3 equation: 



6(3x-2)=9(2x-1)+-3

We move all terms to the left:

6(3x-2)-(9(2x-1)+-3)=0

We use the square of the difference formula

6(3x-2)-(9(2x-1)-3)=0

We multiply parentheses

18x-(9(2x-1)-3)-12=0



We calculate terms in parentheses: -(9(2x-1)-3), so:

9(2x-1)-3

We multiply parentheses

18x-9-3

We add all the numbers together, and all the variables

18x-12

Back to the equation:

-(18x-12)



We get rid of parentheses

18x-18x+12-12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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