6(3x-2)=9(2x-1)+3x

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Solution for 6(3x-2)=9(2x-1)+3x equation: 



6(3x-2)=9(2x-1)+3x

We move all terms to the left:

6(3x-2)-(9(2x-1)+3x)=0

We multiply parentheses

18x-(9(2x-1)+3x)-12=0



We calculate terms in parentheses: -(9(2x-1)+3x), so:

9(2x-1)+3x

We add all the numbers together, and all the variables

3x+9(2x-1)

We multiply parentheses

3x+18x-9

We add all the numbers together, and all the variables

21x-9

Back to the equation:

-(21x-9)



We get rid of parentheses

18x-21x+9-12=0

We add all the numbers together, and all the variables

-3x-3=0

We move all terms containing x to the left, all other terms to the right

-3x=3

x=3/-3

x=-1

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