6(3x-2x)+12x=18

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Solution for 6(3x-2x)+12x=18 equation: 



6(3x-2x)+12x=18

We move all terms to the left:

6(3x-2x)+12x-(18)=0

We add all the numbers together, and all the variables

6(+x)+12x-18=0

We add all the numbers together, and all the variables

12x+6(+x)-18=0

We multiply parentheses

12x+6x-18=0

We add all the numbers together, and all the variables

18x-18=0

We move all terms containing x to the left, all other terms to the right

18x=18

x=18/18

x=1

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