6(3x-3)=4(1+4x)

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Solution for 6(3x-3)=4(1+4x) equation: 



6(3x-3)=4(1+4x)

We move all terms to the left:

6(3x-3)-(4(1+4x))=0

We add all the numbers together, and all the variables

6(3x-3)-(4(4x+1))=0

We multiply parentheses

18x-(4(4x+1))-18=0



We calculate terms in parentheses: -(4(4x+1)), so:

4(4x+1)

We multiply parentheses

16x+4

Back to the equation:

-(16x+4)



We get rid of parentheses

18x-16x-4-18=0

We add all the numbers together, and all the variables

2x-22=0

We move all terms containing x to the left, all other terms to the right

2x=22

x=22/2

x=11

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