6(3x-4)+2x=56

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Solution for 6(3x-4)+2x=56 equation: 



6(3x-4)+2x=56

We move all terms to the left:

6(3x-4)+2x-(56)=0

We add all the numbers together, and all the variables

2x+6(3x-4)-56=0

We multiply parentheses

2x+18x-24-56=0

We add all the numbers together, and all the variables

20x-80=0

We move all terms containing x to the left, all other terms to the right

20x=80

x=80/20

x=4

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