6(3x-4)-10(x-3)-1=10(2x-3)

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Solution for 6(3x-4)-10(x-3)-1=10(2x-3) equation: 



6(3x-4)-10(x-3)-1=10(2x-3)

We move all terms to the left:

6(3x-4)-10(x-3)-1-(10(2x-3))=0

We multiply parentheses

18x-10x-(10(2x-3))-24+30-1=0



We calculate terms in parentheses: -(10(2x-3)), so:

10(2x-3)

We multiply parentheses

20x-30

Back to the equation:

-(20x-30)



We add all the numbers together, and all the variables

8x-(20x-30)+5=0

We get rid of parentheses

8x-20x+30+5=0

We add all the numbers together, and all the variables

-12x+35=0

We move all terms containing x to the left, all other terms to the right

-12x=-35

x=-35/-12

x=2+11/12

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