6(3x-4)-3(2x+2)=-2(x+-1)-4

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Solution for 6(3x-4)-3(2x+2)=-2(x+-1)-4 equation: 



6(3x-4)-3(2x+2)=-2(x+-1)-4

We move all terms to the left:

6(3x-4)-3(2x+2)-(-2(x+-1)-4)=0

We add all the numbers together, and all the variables

6(3x-4)-3(2x+2)-(-2(x-1)-4)=0

We multiply parentheses

18x-6x-(-2(x-1)-4)-24-6=0



We calculate terms in parentheses: -(-2(x-1)-4), so:

-2(x-1)-4

We multiply parentheses

-2x+2-4

We add all the numbers together, and all the variables

-2x-2

Back to the equation:

-(-2x-2)



We add all the numbers together, and all the variables

12x-(-2x-2)-30=0

We get rid of parentheses

12x+2x+2-30=0

We add all the numbers together, and all the variables

14x-28=0

We move all terms containing x to the left, all other terms to the right

14x=28

x=28/14

x=2

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