6(3x-4)-3(2x-5)=x+24

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Solution for 6(3x-4)-3(2x-5)=x+24 equation: 



6(3x-4)-3(2x-5)=x+24

We move all terms to the left:

6(3x-4)-3(2x-5)-(x+24)=0

We multiply parentheses

18x-6x-(x+24)-24+15=0

We get rid of parentheses

18x-6x-x-24-24+15=0

We add all the numbers together, and all the variables

11x-33=0

We move all terms containing x to the left, all other terms to the right

11x=33

x=33/11

x=3

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