6(3x-4)-3(3x-19)=2(4x+1)-1

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Solution for 6(3x-4)-3(3x-19)=2(4x+1)-1 equation: 



6(3x-4)-3(3x-19)=2(4x+1)-1

We move all terms to the left:

6(3x-4)-3(3x-19)-(2(4x+1)-1)=0

We multiply parentheses

18x-9x-(2(4x+1)-1)-24+57=0



We calculate terms in parentheses: -(2(4x+1)-1), so:

2(4x+1)-1

We multiply parentheses

8x+2-1

We add all the numbers together, and all the variables

8x+1

Back to the equation:

-(8x+1)



We add all the numbers together, and all the variables

9x-(8x+1)+33=0

We get rid of parentheses

9x-8x-1+33=0

We add all the numbers together, and all the variables

x+32=0

We move all terms containing x to the left, all other terms to the right

x=-32

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