6(3x-4)=2(4x+12)

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Solution for 6(3x-4)=2(4x+12) equation: 



6(3x-4)=2(4x+12)

We move all terms to the left:

6(3x-4)-(2(4x+12))=0

We multiply parentheses

18x-(2(4x+12))-24=0



We calculate terms in parentheses: -(2(4x+12)), so:

2(4x+12)

We multiply parentheses

8x+24

Back to the equation:

-(8x+24)



We get rid of parentheses

18x-8x-24-24=0

We add all the numbers together, and all the variables

10x-48=0

We move all terms containing x to the left, all other terms to the right

10x=48

x=48/10

x=4+4/5

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