6(3x-4)=5-(x-2)

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Solution for 6(3x-4)=5-(x-2) equation: 



6(3x-4)=5-(x-2)

We move all terms to the left:

6(3x-4)-(5-(x-2))=0

We multiply parentheses

18x-(5-(x-2))-24=0



We calculate terms in parentheses: -(5-(x-2)), so:

5-(x-2)

determiningTheFunctionDomain
-(x-2)+5

We get rid of parentheses

-x+2+5

We add all the numbers together, and all the variables

-1x+7

Back to the equation:

-(-1x+7)



We get rid of parentheses

18x+1x-7-24=0

We add all the numbers together, and all the variables

19x-31=0

We move all terms containing x to the left, all other terms to the right

19x=31

x=31/19

x=1+12/19

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