6(3x-5)-2(x+4)=12

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Solution for 6(3x-5)-2(x+4)=12 equation: 



6(3x-5)-2(x+4)=12

We move all terms to the left:

6(3x-5)-2(x+4)-(12)=0

We multiply parentheses

18x-2x-30-8-12=0

We add all the numbers together, and all the variables

16x-50=0

We move all terms containing x to the left, all other terms to the right

16x=50

x=50/16

x=3+1/8

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