6(3x-5)=-10(x+3)

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Solution for 6(3x-5)=-10(x+3) equation: 



6(3x-5)=-10(x+3)

We move all terms to the left:

6(3x-5)-(-10(x+3))=0

We multiply parentheses

18x-(-10(x+3))-30=0



We calculate terms in parentheses: -(-10(x+3)), so:

-10(x+3)

We multiply parentheses

-10x-30

Back to the equation:

-(-10x-30)



We get rid of parentheses

18x+10x+30-30=0

We add all the numbers together, and all the variables

28x=0

x=0/28

x=0

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