6(3x-5)=7(2x-2)

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Solution for 6(3x-5)=7(2x-2) equation: 



6(3x-5)=7(2x-2)

We move all terms to the left:

6(3x-5)-(7(2x-2))=0

We multiply parentheses

18x-(7(2x-2))-30=0



We calculate terms in parentheses: -(7(2x-2)), so:

7(2x-2)

We multiply parentheses

14x-14

Back to the equation:

-(14x-14)



We get rid of parentheses

18x-14x+14-30=0

We add all the numbers together, and all the variables

4x-16=0

We move all terms containing x to the left, all other terms to the right

4x=16

x=16/4

x=4

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