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6(3x-7)-4=6(x-4)+62
We move all terms to the left:
6(3x-7)-4-(6(x-4)+62)=0
We multiply parentheses
18x-(6(x-4)+62)-42-4=0
We calculate terms in parentheses: -(6(x-4)+62), so:We add all the numbers together, and all the variables
6(x-4)+62
We multiply parentheses
6x-24+62
We add all the numbers together, and all the variables
6x+38
Back to the equation:
-(6x+38)
18x-(6x+38)-46=0
We get rid of parentheses
18x-6x-38-46=0
We add all the numbers together, and all the variables
12x-84=0
We move all terms containing x to the left, all other terms to the right
12x=84
x=84/12
x=7
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