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6(3x-7)-8=6(x-3)+52
We move all terms to the left:
6(3x-7)-8-(6(x-3)+52)=0
We multiply parentheses
18x-(6(x-3)+52)-42-8=0
We calculate terms in parentheses: -(6(x-3)+52), so:We add all the numbers together, and all the variables
6(x-3)+52
We multiply parentheses
6x-18+52
We add all the numbers together, and all the variables
6x+34
Back to the equation:
-(6x+34)
18x-(6x+34)-50=0
We get rid of parentheses
18x-6x-34-50=0
We add all the numbers together, and all the variables
12x-84=0
We move all terms containing x to the left, all other terms to the right
12x=84
x=84/12
x=7
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