6(3x-9)-2=6(x-2)+16

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Solution for 6(3x-9)-2=6(x-2)+16 equation: 



6(3x-9)-2=6(x-2)+16

We move all terms to the left:

6(3x-9)-2-(6(x-2)+16)=0

We multiply parentheses

18x-(6(x-2)+16)-54-2=0



We calculate terms in parentheses: -(6(x-2)+16), so:

6(x-2)+16

We multiply parentheses

6x-12+16

We add all the numbers together, and all the variables

6x+4

Back to the equation:

-(6x+4)



We add all the numbers together, and all the variables

18x-(6x+4)-56=0

We get rid of parentheses

18x-6x-4-56=0

We add all the numbers together, and all the variables

12x-60=0

We move all terms containing x to the left, all other terms to the right

12x=60

x=60/12

x=5

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