6(3x/2+4)-10=1/2(4x+16)

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Solution for 6(3x/2+4)-10=1/2(4x+16) equation: 



6(3x/2+4)-10=1/2(4x+16)

We move all terms to the left:

6(3x/2+4)-10-(1/2(4x+16))=0



Domain of the equation: 2(4x+16))!=0

x∈R



We multiply parentheses

18x-(1/2(4x+16))+24-10=0

We multiply all the terms by the denominator


18x*2(4x+16))-(1+24*2(4x+16))-10*2(4x+16))=0

We add all the numbers together, and all the variables

18x*2(4x+16))-(1+24*2(4x+16))-10*2(4x=0

Wy multiply elements

36x^2(4+96x^2(4=0

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