6(3y+1)+1=-3+8y+5(2y+2)

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Solution for 6(3y+1)+1=-3+8y+5(2y+2) equation:


Simplifying
6(3y + 1) + 1 = -3 + 8y + 5(2y + 2)

Reorder the terms:
6(1 + 3y) + 1 = -3 + 8y + 5(2y + 2)
(1 * 6 + 3y * 6) + 1 = -3 + 8y + 5(2y + 2)
(6 + 18y) + 1 = -3 + 8y + 5(2y + 2)

Reorder the terms:
6 + 1 + 18y = -3 + 8y + 5(2y + 2)

Combine like terms: 6 + 1 = 7
7 + 18y = -3 + 8y + 5(2y + 2)

Reorder the terms:
7 + 18y = -3 + 8y + 5(2 + 2y)
7 + 18y = -3 + 8y + (2 * 5 + 2y * 5)
7 + 18y = -3 + 8y + (10 + 10y)

Reorder the terms:
7 + 18y = -3 + 10 + 8y + 10y

Combine like terms: -3 + 10 = 7
7 + 18y = 7 + 8y + 10y

Combine like terms: 8y + 10y = 18y
7 + 18y = 7 + 18y

Add '-7' to each side of the equation.
7 + -7 + 18y = 7 + -7 + 18y

Combine like terms: 7 + -7 = 0
0 + 18y = 7 + -7 + 18y
18y = 7 + -7 + 18y

Combine like terms: 7 + -7 = 0
18y = 0 + 18y
18y = 18y

Add '-18y' to each side of the equation.
18y + -18y = 18y + -18y

Combine like terms: 18y + -18y = 0
0 = 18y + -18y

Combine like terms: 18y + -18y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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