6(3y+1)-11=5(6y+5)-14

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Solution for 6(3y+1)-11=5(6y+5)-14 equation: 



6(3y+1)-11=5(6y+5)-14

We move all terms to the left:

6(3y+1)-11-(5(6y+5)-14)=0

We multiply parentheses

18y-(5(6y+5)-14)+6-11=0



We calculate terms in parentheses: -(5(6y+5)-14), so:

5(6y+5)-14

We multiply parentheses

30y+25-14

We add all the numbers together, and all the variables

30y+11

Back to the equation:

-(30y+11)



We add all the numbers together, and all the variables

18y-(30y+11)-5=0

We get rid of parentheses

18y-30y-11-5=0

We add all the numbers together, and all the variables

-12y-16=0

We move all terms containing y to the left, all other terms to the right

-12y=16

y=16/-12

y=-1+1/3

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