6(3y+2)+11=3(2y+1)+2

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Solution for 6(3y+2)+11=3(2y+1)+2 equation: 



6(3y+2)+11=3(2y+1)+2

We move all terms to the left:

6(3y+2)+11-(3(2y+1)+2)=0

We multiply parentheses

18y-(3(2y+1)+2)+12+11=0



We calculate terms in parentheses: -(3(2y+1)+2), so:

3(2y+1)+2

We multiply parentheses

6y+3+2

We add all the numbers together, and all the variables

6y+5

Back to the equation:

-(6y+5)



We add all the numbers together, and all the variables

18y-(6y+5)+23=0

We get rid of parentheses

18y-6y-5+23=0

We add all the numbers together, and all the variables

12y+18=0

We move all terms containing y to the left, all other terms to the right

12y=-18

y=-18/12

y=-1+1/2

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