6(3y+3)=6(3y)+6(3)

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Solution for 6(3y+3)=6(3y)+6(3) equation:



6(3y+3)=6(3y)+6(3)
We move all terms to the left:
6(3y+3)-(6(3y)+6(3))=0
We multiply parentheses
18y-(63y+63)+18=0
We get rid of parentheses
18y-63y-63+18=0
We add all the numbers together, and all the variables
-45y-45=0
We move all terms containing y to the left, all other terms to the right
-45y=45
y=45/-45
y=-1

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