6(3y+4)-19=4(6y+1)+21

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Solution for 6(3y+4)-19=4(6y+1)+21 equation: 



6(3y+4)-19=4(6y+1)+21

We move all terms to the left:

6(3y+4)-19-(4(6y+1)+21)=0

We multiply parentheses

18y-(4(6y+1)+21)+24-19=0



We calculate terms in parentheses: -(4(6y+1)+21), so:

4(6y+1)+21

We multiply parentheses

24y+4+21

We add all the numbers together, and all the variables

24y+25

Back to the equation:

-(24y+25)



We add all the numbers together, and all the variables

18y-(24y+25)+5=0

We get rid of parentheses

18y-24y-25+5=0

We add all the numbers together, and all the variables

-6y-20=0

We move all terms containing y to the left, all other terms to the right

-6y=20

y=20/-6

y=-3+1/3

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