6(3y-10)=-7(11-2y)

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Solution for 6(3y-10)=-7(11-2y) equation: 



6(3y-10)=-7(11-2y)

We move all terms to the left:

6(3y-10)-(-7(11-2y))=0

We add all the numbers together, and all the variables

6(3y-10)-(-7(-2y+11))=0

We multiply parentheses

18y-(-7(-2y+11))-60=0



We calculate terms in parentheses: -(-7(-2y+11)), so:

-7(-2y+11)

We multiply parentheses

14y-77

Back to the equation:

-(14y-77)



We get rid of parentheses

18y-14y+77-60=0

We add all the numbers together, and all the variables

4y+17=0

We move all terms containing y to the left, all other terms to the right

4y=-17

y=-17/4

y=-4+1/4

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