6(3y-3)+4=40

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Solution for 6(3y-3)+4=40 equation: 



6(3y-3)+4=40

We move all terms to the left:

6(3y-3)+4-(40)=0

We add all the numbers together, and all the variables

6(3y-3)-36=0

We multiply parentheses

18y-18-36=0

We add all the numbers together, and all the variables

18y-54=0

We move all terms containing y to the left, all other terms to the right

18y=54

y=54/18

y=3

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