6(3y-4)+7=-5(-4+8y)-3(2y-9)

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Solution for 6(3y-4)+7=-5(-4+8y)-3(2y-9) equation:



6(3y-4)+7=-5(-4+8y)-3(2y-9)
We move all terms to the left:
6(3y-4)+7-(-5(-4+8y)-3(2y-9))=0
We add all the numbers together, and all the variables
6(3y-4)-(-5(8y-4)-3(2y-9))+7=0
We multiply parentheses
18y-(-5(8y-4)-3(2y-9))-24+7=0
We calculate terms in parentheses: -(-5(8y-4)-3(2y-9)), so:
-5(8y-4)-3(2y-9)
We multiply parentheses
-40y-6y+20+27
We add all the numbers together, and all the variables
-46y+47
Back to the equation:
-(-46y+47)
We add all the numbers together, and all the variables
18y-(-46y+47)-17=0
We get rid of parentheses
18y+46y-47-17=0
We add all the numbers together, and all the variables
64y-64=0
We move all terms containing y to the left, all other terms to the right
64y=64
y=64/64
y=1

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