6(3z+1)-z-22=1

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Solution for 6(3z+1)-z-22=1 equation: 



6(3z+1)-z-22=1

We move all terms to the left:

6(3z+1)-z-22-(1)=0

We add all the numbers together, and all the variables

-1z+6(3z+1)-23=0

We multiply parentheses

-1z+18z+6-23=0

We add all the numbers together, and all the variables

17z-17=0

We move all terms containing z to the left, all other terms to the right

17z=17

z=17/17

z=1

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