6(3z+1)=2(z+3)

Solution for 6(3z+1)=2(z+3) equation:

Simplifying
6(3z + 1) = 2(z + 3)

Reorder the terms:
6(1 + 3z) = 2(z + 3)
(1 * 6 + 3z * 6) = 2(z + 3)
(6 + 18z) = 2(z + 3)

Reorder the terms:
6 + 18z = 2(3 + z)
6 + 18z = (3 * 2 + z * 2)
6 + 18z = (6 + 2z)

Add '-6' to each side of the equation.
6 + -6 + 18z = 6 + -6 + 2z

Combine like terms: 6 + -6 = 0
0 + 18z = 6 + -6 + 2z
18z = 6 + -6 + 2z

Combine like terms: 6 + -6 = 0
18z = 0 + 2z
18z = 2z

Solving
18z = 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
18z + -2z = 2z + -2z

Combine like terms: 18z + -2z = 16z
16z = 2z + -2z

Combine like terms: 2z + -2z = 0
16z = 0

Divide each side by '16'.
z = 0

Simplifying
z = 0