6(3z+2)=48

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Solution for 6(3z+2)=48 equation: 



6(3z+2)=48

We move all terms to the left:

6(3z+2)-(48)=0

We multiply parentheses

18z+12-48=0

We add all the numbers together, and all the variables

18z-36=0

We move all terms containing z to the left, all other terms to the right

18z=36

z=36/18

z=2

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