6(3z-1)-2(z+1)=3(z+1)

Solution for 6(3z-1)-2(z+1)=3(z+1) equation:

Simplifying
6(3z + -1) + -2(z + 1) = 3(z + 1)

Reorder the terms:
6(-1 + 3z) + -2(z + 1) = 3(z + 1)
(-1 * 6 + 3z * 6) + -2(z + 1) = 3(z + 1)
(-6 + 18z) + -2(z + 1) = 3(z + 1)

Reorder the terms:
-6 + 18z + -2(1 + z) = 3(z + 1)
-6 + 18z + (1 * -2 + z * -2) = 3(z + 1)
-6 + 18z + (-2 + -2z) = 3(z + 1)

Reorder the terms:
-6 + -2 + 18z + -2z = 3(z + 1)

Combine like terms: -6 + -2 = -8
-8 + 18z + -2z = 3(z + 1)

Combine like terms: 18z + -2z = 16z
-8 + 16z = 3(z + 1)

Reorder the terms:
-8 + 16z = 3(1 + z)
-8 + 16z = (1 * 3 + z * 3)
-8 + 16z = (3 + 3z)

Solving
-8 + 16z = 3 + 3z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-3z' to each side of the equation.
-8 + 16z + -3z = 3 + 3z + -3z

Combine like terms: 16z + -3z = 13z
-8 + 13z = 3 + 3z + -3z

Combine like terms: 3z + -3z = 0
-8 + 13z = 3 + 0
-8 + 13z = 3

Add '8' to each side of the equation.
-8 + 8 + 13z = 3 + 8

Combine like terms: -8 + 8 = 0
0 + 13z = 3 + 8
13z = 3 + 8

Combine like terms: 3 + 8 = 11
13z = 11

Divide each side by '13'.
z = 0.8461538462

Simplifying
z = 0.8461538462