6(3z-1)-2(z+2)=7(z+1)

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Solution for 6(3z-1)-2(z+2)=7(z+1) equation:


Simplifying
6(3z + -1) + -2(z + 2) = 7(z + 1)

Reorder the terms:
6(-1 + 3z) + -2(z + 2) = 7(z + 1)
(-1 * 6 + 3z * 6) + -2(z + 2) = 7(z + 1)
(-6 + 18z) + -2(z + 2) = 7(z + 1)

Reorder the terms:
-6 + 18z + -2(2 + z) = 7(z + 1)
-6 + 18z + (2 * -2 + z * -2) = 7(z + 1)
-6 + 18z + (-4 + -2z) = 7(z + 1)

Reorder the terms:
-6 + -4 + 18z + -2z = 7(z + 1)

Combine like terms: -6 + -4 = -10
-10 + 18z + -2z = 7(z + 1)

Combine like terms: 18z + -2z = 16z
-10 + 16z = 7(z + 1)

Reorder the terms:
-10 + 16z = 7(1 + z)
-10 + 16z = (1 * 7 + z * 7)
-10 + 16z = (7 + 7z)

Solving
-10 + 16z = 7 + 7z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-7z' to each side of the equation.
-10 + 16z + -7z = 7 + 7z + -7z

Combine like terms: 16z + -7z = 9z
-10 + 9z = 7 + 7z + -7z

Combine like terms: 7z + -7z = 0
-10 + 9z = 7 + 0
-10 + 9z = 7

Add '10' to each side of the equation.
-10 + 10 + 9z = 7 + 10

Combine like terms: -10 + 10 = 0
0 + 9z = 7 + 10
9z = 7 + 10

Combine like terms: 7 + 10 = 17
9z = 17

Divide each side by '9'.
z = 1.888888889

Simplifying
z = 1.888888889

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