6(3z-1)-4(z=4)=7(z+1)

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Solution for 6(3z-1)-4(z=4)=7(z+1) equation: 



6(3z-1)-4(z=4)=7(z+1)

We move all terms to the left:

6(3z-1)-4(z-(4))=0

We multiply parentheses

18z-4z-6+16=0

We add all the numbers together, and all the variables

14z+10=0

We move all terms containing z to the left, all other terms to the right

14z=-10

z=-10/14

z=-5/7

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