6(3z-1)=-6+18z

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Solution for 6(3z-1)=-6+18z equation: 



6(3z-1)=-6+18z

We move all terms to the left:

6(3z-1)-(-6+18z)=0

We add all the numbers together, and all the variables

6(3z-1)-(18z-6)=0

We multiply parentheses

18z-(18z-6)-6=0

We get rid of parentheses

18z-18z+6-6=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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