6(3z-1)=-6+18z

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Solution for 6(3z-1)=-6+18z equation:



6(3z-1)=-6+18z
We move all terms to the left:
6(3z-1)-(-6+18z)=0
We add all the numbers together, and all the variables
6(3z-1)-(18z-6)=0
We multiply parentheses
18z-(18z-6)-6=0
We get rid of parentheses
18z-18z+6-6=0
We add all the numbers together, and all the variables
=0
z=0/1
z=0

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